解方程组：(x-2)^2+(y+3)^2=9 , 3x-2y=6

(x-2)^2+(y+3)^2=9 .............(1)
3x-2y=6.........................(2)

把（2）式化简为x=2+2y/3 带入（1）式得
（2+2y/3-2）^2+（y^2+6y+9）=9
4y^2/9+y^2+6y+9=9
y(13y/9+6)=0
解 y1=0,y2=-6/(13/9)=-54/13
把y1,y2带入（2）式得
x1=6/3=2
x2=（6-54/13*2）/3=-10/13
即方程组得解为
x1=2, y1=0
x2=-10/13, y2=-54/13

3x-2y=6
=>2y=3x-6
(x-2)^2+(y+3)^2=9
=>4(x-2)^2+4(y+3)^2=36
=>4(x-2)^2+(2y+6)^2=36
=>4(x-2)^2+(3x)^2=36
=>
4(x^2-4x+4)+9x^2-36
=4x^2-16x+16+9x^2-36
=13x^2-16x-20
=(13x+10)(x-2)
=0
=>x=-10/13 or x=2
=>x=-10/13,y=-54/13
or
x=2,y=0(不合)
=>x=-10/13,y=-54/13